[Python3] 412. Fizz Buzz

[412. Fizz Buzz] (https://leetcode.com/problems/fizz-buzz/)

if

a basic solution with if

class Solution:

    def fizzBuzz(self, n: int) -> List[str]:

        list = []

        for i in range(1, n+1):
            if i%15==0:
                list.append("FizzBuzz")
            elif i%5==0:
                list.append("Buzz")
            elif i%3==0:
                list.append("Fizz")
            else:
                list.append(str(i))

        return list

list comprehension

make each conditions as a flag with true or false.

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        return [str(i) * (i % 3 != 0 and i % 5 != 0) + "Fizz" * (i % 3 == 0) + "Buzz" * (i % 5 == 0) for i in range(1, n + 1)]

define function

it's the slowest.

class Solution:

    def fillList(self, n):
        if n%15==0:
            return "FizzBuzz"
        elif n%5==0:
            return "Buzz"
        elif n%3==0:
            return "Fizz"
        else:
            return str(n)

    def fizzBuzz(self, n: int) -> List[str]:
        list = []
        for i in range(1, n+1):
            list.append(self.fillList(i))
        return list

In comparison with Java

class Solution {

    public String fillList(int n){
        if(n%15==0) return "FizzBuzz";
        else if(n%3==0) return "Fizz";
        else if(n%5==0) return "Buzz";
        else return Integer.toString(n);
    }

    public List<String> fizzBuzz(int n) {

        List<String> res = new ArrayList<String>();

        for(int i=1; i<=n; i++){
            res.add(fillList(i));
        }

        return res;

    }
}